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2x^2-6.4x+2.16=0
a = 2; b = -6.4; c = +2.16;
Δ = b2-4ac
Δ = -6.42-4·2·2.16
Δ = 23.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.4)-\sqrt{23.68}}{2*2}=\frac{6.4-\sqrt{23.68}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.4)+\sqrt{23.68}}{2*2}=\frac{6.4+\sqrt{23.68}}{4} $
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